Question

Code

class Solution:
    def validWordAbbreviation(self, word: str, abbr: str) -> bool:
        count = 0
        i = 0
        
        while i < len(abbr):
            # Check for invalid cases: leading zeros or count overflow
            if abbr[i] == '0' or count >= len(word):
                return False
            
            # Handle numbers
            number = ''
            while i < len(abbr) and abbr[i].isdigit():
                number += abbr[i]
                i += 1
            
            # Update count based on number or letter
            if number:
                count += int(number)
            else:
                if abbr[i] != word[count]:
                    return False
                count += 1
                i += 1
        
        return count == len(word)