323. Number of Connected Components in an Undirected Graph
Question

Code
- used union find to solve the issue
class Solution(object):
def countComponents(self, n, edges):
parent = [i for i in range(n)]
rank = [1] * n
def find(x):
res = x
while res != parent[res]:
parent[res] = parent[parent[res]]
res = parent[res]
return res
def union(n1, n2):
p1, p2 = find(n1), find(n2)
if p1 == p2:
return 0
if rank[p1] < rank[p2]:
parent[p1] = p2
rank[p2] += rank[p1]
else:
parent[p2] = p1
rank[p1] += rank[p2]
return 1
res = n
for n1, n2 in edges:
res -= union(n1, n2)
return res