1717. Maximum Score From Removing Substrings

Question

CleanShot 2024-10-20 at 17.19.17@2x.png

Code

CleanShot 2024-10-20 at 17.18.40@2x.png

class Solution:
    def maximumGain(self, s: str, x: int, y: int) -> int:
        total_score = 0
        high_priority_pair = "ab" if x > y else "ba"
        low_priority_pair = "ba" if high_priority_pair == "ab" else "ab"

        # First pass: remove high priority pair
        string_after_first_pass = self.remove_substring(s, high_priority_pair)
        removed_pairs_count = (len(s) - len(string_after_first_pass)) // 2

        # Calculate score from first pass
        total_score += removed_pairs_count * max(x, y)

        # Second pass: remove low priority pair
        string_after_second_pass = self.remove_substring(
            string_after_first_pass, low_priority_pair
        )
        removed_pairs_count = (
            len(string_after_first_pass) - len(string_after_second_pass)
        ) // 2

        # Calculate score from second pass
        total_score += removed_pairs_count * min(x, y)

        return total_score

    def remove_substring(self, input: str, target_pair: str) -> str:
        char_stack = []

        # Iterate through each character in the input string
        for current_char in input:
            # Check if current character forms the target pair with the top of the stack
            if (
                current_char == target_pair[1]
                and char_stack
                and char_stack[-1] == target_pair[0]
            ):
                char_stack.pop()  # Remove the matching character from the stack
            else:
                char_stack.append(current_char)

        # Reconstruct the remaining string after removing target pairs
        return "".join(char_stack)